package q172

// Note: actually, counting 5 alone is enough since 2 certainly occurs more than 5.

func trailingZeroes(n int) int {
	count2, count5 := 0, 0
	for i := 2; i <= n; i++ {
		num := i
		for num%2 == 0 {
			num /= 2
			count2++
		}
		for num%5 == 0 {
			num /= 5
			count5++
		}
	}
	return min(count2, count5)
}

var _ = trailingZeroes