add new solutions
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46
solutions/14/q1415/solution.go
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46
solutions/14/q1415/solution.go
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// Package q1415 implements a solution for https://leetcode.com/problems/the-k-th-lexicographical-string-of-all-happy-strings-of-length-n/
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package q1415
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import (
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"math"
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"strings"
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)
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func getHappyString(n, k int) string {
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// The base is ababababab...
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// Behaves like binary, except the first character, which has three choices: a, b, c.
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// Max of k is 2^n + 2^(n-1)
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if k > int(math.Pow(2, float64(n))+math.Pow(2, float64(n-1))) {
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return ""
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}
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k -= 1
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sb := strings.Builder{}
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var last byte
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switch k >> (n - 1) {
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case 0:
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last = 'a'
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case 1:
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last = 'b'
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case 2:
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last = 'c'
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}
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sb.WriteByte(last)
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lut := [][2]byte{
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{'b', 'c'},
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{'a', 'c'},
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{'a', 'b'},
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}
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for i := n - 1; i > 0; i-- {
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lookup := k >> (i - 1) & 1
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c := lut[last-'a'][lookup]
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sb.WriteByte(c)
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last = c
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}
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return sb.String()
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}
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var _ = getHappyString
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68
solutions/16/q1622/solution.go
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68
solutions/16/q1622/solution.go
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// Package q1622 implements a solution for https://leetcode.com/problems/fancy-sequence/
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// ref: https://en.wikipedia.org/wiki/Fermat%27s_little_theorem
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package q1622
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const MOD int = 1e9 + 7
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type Fancy struct {
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numbers []int
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states []fancyState // this can be optimized out
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add, mul, inv int
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}
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type fancyState struct{ add, inv int }
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func Constructor() Fancy {
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return Fancy{
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numbers: make([]int, 0, 128),
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states: make([]fancyState, 0, 128),
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mul: 1,
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inv: 1,
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}
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}
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// findInv calculates num^(MOD-2), which is the inverse of num under mod MOD
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// when MOD is a prime number. `inv(num) * num % MOD == 1`.
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func findInv(num int) int {
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pow := MOD - 2
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ret := 1
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cur := num % MOD
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for i := 1; 1<<(i-1) <= pow; i++ {
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if (pow>>(i-1))&1 == 1 {
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ret = (ret * cur) % MOD
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}
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cur = cur * cur % MOD
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}
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return ret
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}
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func (f *Fancy) Append(val int) {
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f.numbers = append(f.numbers, val)
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f.states = append(f.states, fancyState{add: f.add, inv: f.inv})
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}
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func (f *Fancy) AddAll(inc int) { f.add = (f.add + inc) % MOD }
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func (f *Fancy) MultAll(m int) {
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f.mul = f.mul * m % MOD
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f.add = f.add * m % MOD
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f.inv = findInv(f.mul)
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}
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func (f *Fancy) GetIndex(idx int) int {
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if idx >= len(f.numbers) {
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return -1
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}
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num := f.numbers[idx] * f.mul % MOD * f.states[idx].inv % MOD
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savedAdd := f.states[idx].add * f.mul % MOD * f.states[idx].inv % MOD
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return (num + MOD + f.add - savedAdd) % MOD
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}
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/**
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* Your Fancy object will be instantiated and called as such:
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* obj := Constructor();
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* obj.Append(val);
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* obj.AddAll(inc);
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* obj.MultAll(m);
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* param_4 := obj.GetIndex(idx);
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*/
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40
solutions/18/q1888/solution.go
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40
solutions/18/q1888/solution.go
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// Package q1888 implements a solution for https://leetcode.com/problems/minimum-number-of-flips-to-make-the-binary-string-alternating/
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package q1888
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// Note: O(1) space is possible.
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var buf = make([][2]int, 1e5)
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func minFlips(s string) int {
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backward := buf[:len(s)]
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from0, from1 := 0, 0
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var alt byte = 0 // alternating byte
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for i := len(s) - 1; i >= 0; i-- {
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if s[i]-'0' == alt {
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from1++
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} else {
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from0++
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}
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alt = alt ^ 1
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backward[i] = [2]int{from0, from1}
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}
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minCost := min(backward[0][0], backward[0][1])
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from0, from1 = 0, 0
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for i := range len(s) - 1 {
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if s[i]-'0' == byte(i%2) {
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from1++
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} else {
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from0++
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}
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minCost = min(
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minCost,
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from0+backward[i+1][1],
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from1+backward[i+1][0],
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)
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}
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return minCost
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}
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var _ = minFlips
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37
solutions/19/q1980/solution.go
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37
solutions/19/q1980/solution.go
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// Package q1980 implements a solution for https://leetcode.com/problems/find-unique-binary-string/
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package q1980
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import "slices"
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func toNumber(s string) int {
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ret := 0
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for i := range len(s) {
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ret = ret<<1 + int(s[i]-'0')
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}
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return ret
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}
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func fromNumber(n, length int) string {
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buf := make([]byte, length)
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for i := range length {
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buf[i] = byte(n&1) + '0'
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n >>= 1
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}
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slices.Reverse(buf)
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return string(buf)
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}
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func findDifferentBinaryString(nums []string) string {
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slices.Sort(nums)
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last := -1
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for i := range nums {
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num := toNumber(nums[i])
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if num > last+1 {
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break
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}
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last = num
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}
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return fromNumber(last+1, len(nums[0]))
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}
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var _ = findDifferentBinaryString
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48
solutions/35/q3567/solution.go
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48
solutions/35/q3567/solution.go
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// Package q3567 implements a solution for https://leetcode.com/problems/minimum-absolute-difference-in-sliding-submatrix/
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package q3567
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import "slices"
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var buf = make([]int, 30*30)
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const INF = 1<<63 - 1
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func minAbsDiffK(grid [][]int, xOffset, k int) int {
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if k == 1 {
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return 0
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}
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numbers := buf[:0]
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for y := range k {
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for x := range k {
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numbers = append(numbers, grid[y][x+xOffset])
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}
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}
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slices.Sort(numbers)
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minDiff := INF
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for i := 1; i < len(numbers); i++ {
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if numbers[i] == numbers[i-1] {
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continue
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}
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minDiff = min(minDiff, numbers[i]-numbers[i-1])
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}
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if minDiff == INF {
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return 0
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}
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return minDiff
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}
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func minAbsDiff(grid [][]int, k int) [][]int {
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w, h := len(grid[0]), len(grid)
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for i := 0; i < h-k+1; i++ {
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for j := 0; j < w-k+1; j++ {
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grid[i][j] = minAbsDiffK(grid[i:], j, k)
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}
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}
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for i := range h - k + 1 {
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grid[i] = grid[i][:w-k+1]
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}
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return grid[:h-k+1]
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}
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var _ = minAbsDiff
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19
solutions/36/q3643/solution.go
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19
solutions/36/q3643/solution.go
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// Package q3643 implements a solution for https://leetcode.com/problems/flip-square-submatrix-vertically/
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package q3643
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func reverseSubmatrix(grid [][]int, x int, y int, k int) [][]int {
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x, y = y, x // lol
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swapBuf := make([]int, k)
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for i := range k / 2 {
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y1 := y + i
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y2 := y + k - 1 - i
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copy(swapBuf, grid[y1][x:x+k])
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copy(grid[y1][x:x+k], grid[y2][x:x+k])
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copy(grid[y2][x:x+k], swapBuf)
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}
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return grid
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}
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var _ = reverseSubmatrix
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