add new solutions

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Yiyang Kang 2026-03-21 14:44:38 +09:00
parent 7d2a6718b3
commit 1f0aa6d417
Signed by: kkyy
SSH key fingerprint: SHA256:lJSbAzC3MvrSORdvIVK6h/3g+rVKJNzM7zq0MgA9WKY
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// Package q1622 implements a solution for https://leetcode.com/problems/fancy-sequence/
// ref: https://en.wikipedia.org/wiki/Fermat%27s_little_theorem
package q1622
const MOD int = 1e9 + 7
type Fancy struct {
numbers []int
states []fancyState // this can be optimized out
add, mul, inv int
}
type fancyState struct{ add, inv int }
func Constructor() Fancy {
return Fancy{
numbers: make([]int, 0, 128),
states: make([]fancyState, 0, 128),
mul: 1,
inv: 1,
}
}
// findInv calculates num^(MOD-2), which is the inverse of num under mod MOD
// when MOD is a prime number. `inv(num) * num % MOD == 1`.
func findInv(num int) int {
pow := MOD - 2
ret := 1
cur := num % MOD
for i := 1; 1<<(i-1) <= pow; i++ {
if (pow>>(i-1))&1 == 1 {
ret = (ret * cur) % MOD
}
cur = cur * cur % MOD
}
return ret
}
func (f *Fancy) Append(val int) {
f.numbers = append(f.numbers, val)
f.states = append(f.states, fancyState{add: f.add, inv: f.inv})
}
func (f *Fancy) AddAll(inc int) { f.add = (f.add + inc) % MOD }
func (f *Fancy) MultAll(m int) {
f.mul = f.mul * m % MOD
f.add = f.add * m % MOD
f.inv = findInv(f.mul)
}
func (f *Fancy) GetIndex(idx int) int {
if idx >= len(f.numbers) {
return -1
}
num := f.numbers[idx] * f.mul % MOD * f.states[idx].inv % MOD
savedAdd := f.states[idx].add * f.mul % MOD * f.states[idx].inv % MOD
return (num + MOD + f.add - savedAdd) % MOD
}
/**
* Your Fancy object will be instantiated and called as such:
* obj := Constructor();
* obj.Append(val);
* obj.AddAll(inc);
* obj.MultAll(m);
* param_4 := obj.GetIndex(idx);
*/